x^2-640x-24000=0

Solution for x^2-640x-24000=0 equation:

x^2-640x-24000=0

a = 1; b = -640; c = -24000;
Δ = b2-4ac
Δ = -6402-4·1·(-24000)
Δ = 505600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{505600}=\sqrt{6400*79}=\sqrt{6400}*\sqrt{79}=80\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-640)-80\sqrt{79}}{2*1}=\frac{640-80\sqrt{79}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-640)+80\sqrt{79}}{2*1}=\frac{640+80\sqrt{79}}{2}
$